Calculus help -- solved I think

[JohnCU]

Prove the statement using the E, S definition of a limit.

The limit of c as x -> a is c.

If E > 0, then S > 0 such that if 0 < | x - a | < S, then (c - c) < E. I think? so 0 < E.

okay so, E is > 0, so S > 0.

 

[RossGr]

More informating is needed. What is c? How is it related to x? How is it related to a? What are the givens for this problem? Since I have no defined relationship between the given symbols I cannot prove anything.

 

[JohnCU]

C is a constant... umm that's all the information available. The limit of c as x -> a is one of the limit laws, I'm just trying to prove it.

 

[eLiu]

That's what..just a restatment of the epsilon-delta definition of a limit?

Here is what you're looking for.

Neat little animated example

More step-by-step explanation

(all this b/c i'm too lazy to type up what it is...hehe)