f(theta) = 4cos(theta) + 2 Find the slope of the tangent line at the pole
i've gotten as far as dy/dx which is
4cos(2theta)+2cos(theta)
-4sin(2theta)-sin(theta)
the answer is sqare root of 3 but we're stuck at dy/dx because we don't know an angle to plug in and zero doesn't work
any suggestions would be greatly appreciated.
i've gotten as far as dy/dx which is
4cos(2theta)+2cos(theta)
-4sin(2theta)-sin(theta)
the answer is sqare root of 3 but we're stuck at dy/dx because we don't know an angle to plug in and zero doesn't work
any suggestions would be greatly appreciated.
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