Calculate Volume

[Sentinel]

Originally posted by: Toastedlightly
Well there seems to be inner and outer diameters?

Yes, just figure the inner diameter because that is where the sand is going.

 

[95SS]

From the problem you posted, the end caps take up volume, since they fit inside the casing. Even the element takes up a minute amount.

 

[Sentinel]

oh crap i forgot about the element

 

[95SS]

3.5*.5^2*pi = 2.748891 cu in
Element = .015 cu in

2.748891 - 0.015 = 2.733891 cu in

 

[smc13]

Well. If I put the vol of 2.73 and and a height of 4 and solve for D, it works.

vol=L*r*r*pi
2.73=4*r*r*3.14
.6825=3.14*r^2
.21735=r^2
.466=r

d=2*r
so d is about 1

there must be something I am missing

 

[Sentinel]

dupe

 

[Sentinel]

3.1416*.5*.5*4-.02-.25

I almost got it to work but it seems messed up because I can't use casing dia, so...maybe the end caps take away too?

 

[95SS]

Originally posted by: Sentinel
3.1416*.5*.5*4-.02-.25

I almost got it to work but it seems messed up because I can't use casing dia, so...maybe the end caps take away too?

Your casing is 4" long. Each endcap is .25" The endcaps fit into the casing. The element touches the endcaps. So the effective dimensions of the cylinder are 3.5" long with a 1" diameter. So:

4-.25-.25=3.5

3.5*(.5^2)*3.14159 = 2.748891 cu in

Now, the element is .02" x .25" x 3.5". So it's volume is

.02*.25*3.5 = .015 cu in

Subtracting gives you 2.748891-.015=2.733891, rounded to two decimal points equals 2.73.

It works for all three examples. Not very difficult at all.

 

[So]

Originally posted by: Sentinel
negative, Pi doesn't have to be exact it just has to figure the equation, here 3.14159265 if it makes you feel better

I will only be happy when you set PI = this, yes, sum to infinity!