calc integration

[crazeinc]

S = integration sign
S(x+2)/(x^2+4x+1) dx

u= x^2+4x+1
du = 2x+4

1/2 S du/u dx
1/2 ln |u| + c
1/2 ln |(x^2+4x+1)| + c

yes, no? I'm drawing a blank.

 

[chuckywang]

yes

 

[DanJ]

Thank God I'm done with that. I don't even want to think about thinking about this anymore.

 

[elmer92413]

Heaven help me I still have to finish my math...!!!

 

[otispunkmeyer]

Originally posted by: crazeinc
S = integration sign
S(x+2)/(x^2+4x+1) dx

u= x^2+4x+1
du = 2x+4

1/2 S du/u dx
1/2 ln |u| + c
1/2 ln |(x^2+4x+1)| + c

yes, no? I'm drawing a blank.

yeh thats right i think

you can also do it partial fractions style by factorising the bottom and putting each term under A and B but since the top is a derivative of the bottom you can skip that

 

[elmer92413]

Originally posted by: otispunkmeyer

Originally posted by: crazeinc
S = integration sign
S(x+2)/(x^2+4x+1) dx

u= x^2+4x+1
du = 2x+4

1/2 S du/u dx
1/2 ln |u| + c
1/2 ln |(x^2+4x+1)| + c

yes, no? I'm drawing a blank.

yeh thats right i think

you can also do it partial fractions style by factorising the bottom and putting each term under A and B but since the top is a derivative of the bottom you can skip that

Thanks for reminding me about partial fractions I have a quiz on that coming up...!!!

 

[skyking]

oh god, it looks right.....

My eyes! I hated that stuff!

 

[otispunkmeyer]

Originally posted by: otispunkmeyer

Originally posted by: crazeinc
S = integration sign
S(x+2)/(x^2+4x+1) dx

u= x^2+4x+1
du = 2x+4

1/2 S du/u dx
1/2 ln |u| + c
1/2 ln |(x^2+4x+1)| + c

yes, no? I'm drawing a blank.

yeh thats right i think

you can also do it partial fractions style by factorising the bottom and putting each term under A and B but since the top is a derivative of the bottom you can skip that

sorry u cant do partial fractions because of the 1

(X^2 + 4X + 1) cant be factorised since to get a 1 you need a 1 and a 1, but then (x+1)(x+1) = x^2 + 2x +1


integral : f'(x)/f(x) = ln |f(x)|+c

so yes your right

 

[chuckywang]

Originally posted by: otispunkmeyer

Originally posted by: otispunkmeyer

Originally posted by: crazeinc
S = integration sign
S(x+2)/(x^2+4x+1) dx

u= x^2+4x+1
du = 2x+4

1/2 S du/u dx
1/2 ln |u| + c
1/2 ln |(x^2+4x+1)| + c

yes, no? I'm drawing a blank.

yeh thats right i think

you can also do it partial fractions style by factorising the bottom and putting each term under A and B but since the top is a derivative of the bottom you can skip that

sorry u cant do partial fractions because of the 1

(X^2 + 4X + 1) cant be factorised since to get a 1 you need a 1 and a 1, but then (x+1)(x+1) = x^2 + 2x +1

QFT! Technically you can do partial fractions, since the roots are real. However, it would be a bitch cause the roots are not nice. OP did it the way the calc textbooks want you to. Just remember, if it's too hard, you're probably doing it wrong.

 

[otispunkmeyer]

Originally posted by: chuckywang

Originally posted by: otispunkmeyer

Originally posted by: otispunkmeyer

Originally posted by: crazeinc
S = integration sign
S(x+2)/(x^2+4x+1) dx

u= x^2+4x+1
du = 2x+4

1/2 S du/u dx
1/2 ln |u| + c
1/2 ln |(x^2+4x+1)| + c

yes, no? I'm drawing a blank.

yeh thats right i think

you can also do it partial fractions style by factorising the bottom and putting each term under A and B but since the top is a derivative of the bottom you can skip that

sorry u cant do partial fractions because of the 1

(X^2 + 4X + 1) cant be factorised since to get a 1 you need a 1 and a 1, but then (x+1)(x+1) = x^2 + 2x +1

QFT! Technically you can do partial fractions, since the roots are real. However, it would be a bitch cause the roots are not nice. OP did it the way the calc textbooks want you to. Just remember, if it's too hard, you're probably doing it wrong.

yep already corrected myself.....remembered the formula for when you have a derivative of a fucntion over the function.

 

[Siva]

i haven't taken calc forever and i have college credit for the ap test. now i'm taking calc based physics and then calc 2 next year, i'm gonna fail

 

[Deeko]

Thank god I'm done with Calculus......

oh wait, I have double integrals galore in my prob/stat class. Damnit.

 

[crazeinc]

I have a test in six hours, unfortunately. These calculus classes really have been a miserable experience. If you actually like doing this stuff, please let me know your secret, because I was thinking about continuing with calc 3 in the fall because I like to watch my hair recede.

 

[Deeko]

Originally posted by: crazeinc
I have a test in six hours, unfortunately. These calculus classes really have been a miserable experience. If you actually like doing this stuff, please let me know your secret, because I was thinking about continuing with calc 3 in the fall because I like to watch my hair recede.

I had to take 4 calc courses...

My brother just graduated a year ago with a degree in math, with aspirations of starting out as a HS math teacher, eventually getting more advanced degrees and moving on to college teaching/research. I'm very much like my brother....but definitely not when it comes to doing math. I'm pretty good at it, but I hate it.

 

[crazeinc]

My BS degree only requires me to take 2, but I was contemplating grad school and would prefer more math on the transcript. That having been said, I can't imagine enduring more of this.

 

[chuckywang]

Call me crazy, but I kinda like calculus. It gives me the satisfaction of solving problems. You just got to do a lot of examples to get good.