Calc 1 Help

[cyberfuzz]

i really dont see how this has to do with what we are doing currently in calc, but the instructor tossed this problem in for the hell of it.

Area: A rancher has 200 feet of fencing with which to enclose two adjacent rectangular corrals. What dimentions should be used so that the enclosure area will be maximum.

________
l.......l.........l
l.......l.........l Y
l___l____l
X .........X

Dotted lines are put there to make picture work. how do i show this as an equation?

 

[BigJ]

I'd imagine you setup an equation, get it in the form of y =, take the derivative, and find the absolute maximum.

 

[shuan24]

40x40x40x40x40

 

[Heisenberg]

Write equation for area, take derivative and set equal to zero, solve for lengths needed.

 

[MrDudeMan]

ah the good old days of calculus 1. find a function, take the derivative, set it equal to 0 and solve.

 

[MrChad]

f(x) = 2xy
200 = 4x + 3y

Combine equations.
Find max, find values for x and y.

 

[maziwanka]

100x100

 

[Wheatmaster]

make formula, take derviative and set the function equal to zero, get your x, plug back into original formula, get dimensions. it's called optimization.

 

[Goosemaster]

Originally posted by: Bigsm00th
ah the good old days of calculus 1. find a function, take the derivative, set it equal to 0 and solve.

"...and by the moonlight, as our luscious bodies caressed each other, we proceeded to integrate...."


hmmm....

 

[Goosemaster]

1st f'(x) ....max/min

 

[Random Variable]

area=2xy
perimeter=4x+2y=200

substitute
[100y-y^2]'=100-2y=0; y=50

[200x-4x^2]'=200-8x; x=25

EDIT: Errr...that's not correct. I forgot the fence between the two corrals.