- Feb 13, 2003
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So I've gotten a new phone recently and I'd like to put Cyanogenmod on it. However, I don't see it on the officially supported devices nor do I see it on the unofficially supported devices.
So I assume I gotta port it myself. Fine, I'd like to learn something new and I'm a software developer by profession so I figure I can figure it out. Plus maybe it'll make someone else with my phone happy, haha.
I've been looking on XDA Developers and YouTube but I can't seem to piece together what exactly I need to do. So far, I've followed Android ROM Development from Source to End on XDA Developers. I've gotten Ubuntu on VirtualBox and the source from Github downloaded. I get to the part about "Building a ROM for a Particular Device" and I'm not sure where to go from here. I assume I base my ROM off a ROM from a similar phone but I don't even know if that's correct. Most guides I've read just say something like "find the correct device tree for your device" or something like that it seems.
Can anyone point me in the right direction here? My phone is the LG Ultimate 2, by the way; I can provide more info if you need it.
Thanks a ton!
So I assume I gotta port it myself. Fine, I'd like to learn something new and I'm a software developer by profession so I figure I can figure it out. Plus maybe it'll make someone else with my phone happy, haha.
I've been looking on XDA Developers and YouTube but I can't seem to piece together what exactly I need to do. So far, I've followed Android ROM Development from Source to End on XDA Developers. I've gotten Ubuntu on VirtualBox and the source from Github downloaded. I get to the part about "Building a ROM for a Particular Device" and I'm not sure where to go from here. I assume I base my ROM off a ROM from a similar phone but I don't even know if that's correct. Most guides I've read just say something like "find the correct device tree for your device" or something like that it seems.
Can anyone point me in the right direction here? My phone is the LG Ultimate 2, by the way; I can provide more info if you need it.
Thanks a ton!