Originally posted by: rpbri2886
This is old stuff from high school, but I cannot for the life of me remember how to do it.
How would i solve the following using factoring:
6x^3 - 54x = 0
Any help would be appreciated, let's avoid the flaming if at all possible.
-Thanks in Advance AT,
Brian
Originally posted by: BigJ
Look at it this way, theres an x and a multiple of 6 as a part of both of them.
So... 6x(x^2 - 9) = 0
6x = 0
x = 0
x^2-9 = 0
x^2 = 9
x = +/- 3
Then check to make sure each solution works.