Originally posted by: badmouse
I took it about a million years ago. I think it still had questions about vaccuum tube cooling on it. It's probably changed a lot since then.
Originally posted by: Ameesh
from my friends who have taken it, there are a lot of theory of computing questions so make sure you bone up on that.
Originally posted by: ggavinmoss
Originally posted by: Ameesh
from my friends who have taken it, there are a lot of theory of computing questions so make sure you bone up on that.
CS GRE: Revenge of the Pumping Lemma!
:shocked:
-geoff
Originally posted by: johnjbruin
Originally posted by: ggavinmoss
Originally posted by: Ameesh
from my friends who have taken it, there are a lot of theory of computing questions so make sure you bone up on that.
CS GRE: Revenge of the Pumping Lemma!
:shocked:
-geoff
LAMO - pumping lemma - brings back memories
The Pumping Lemma
Any regular language L has a magic number p
And any long-enough word in L has the following property:
Amongst its first p symbols is a segment you can find
Whose repetition or omission leaves x amongst its kind.
So if you find a language L which fails this acid test,
And some long word you pump becomes distinct from all the rest,
By contradiction you have shown that language L is not
A regular guy, resiliant to the damage you have wrought.
But if, upon the other hand, x stays within its L,
Then either L is regular, or else you chose not well.
For w is xyz, and y cannot be null,
And y must come before p symbols have been read in full.
Originally posted by: Ameesh
Originally posted by: johnjbruin
Originally posted by: ggavinmoss
Originally posted by: Ameesh
from my friends who have taken it, there are a lot of theory of computing questions so make sure you bone up on that.
CS GRE: Revenge of the Pumping Lemma!
:shocked:
-geoff
LAMO - pumping lemma - brings back memories
The Pumping Lemma
Any regular language L has a magic number p
And any long-enough word in L has the following property:
Amongst its first p symbols is a segment you can find
Whose repetition or omission leaves x amongst its kind.
So if you find a language L which fails this acid test,
And some long word you pump becomes distinct from all the rest,
By contradiction you have shown that language L is not
A regular guy, resiliant to the damage you have wrought.
But if, upon the other hand, x stays within its L,
Then either L is regular, or else you chose not well.
For w is xyz, and y cannot be null,
And y must come before p symbols have been read in full.
the pumping lemma makes baby jesus cry