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Anyone know how to do this trig problem?

if -3,-4 is the point on the terminal side, then using arctan, we can see that the angle terminating in Quadrant III is 53 degrees.

so that means the angle with respect to the origin is -143 degrees. (-90 from going backwards through Quad IV and then the additional 53).

so tan(-143) = 0.754

i think i did this wrong, but whatever
 
You've got to be kidding me!! You couldn't just type that problem in? You had to scan it and upload the gif???

n/m I see you're not the one to put it online.
 
Anyway, .754 isn't an exact value.
3rd quadrant...
draw a right triangle in the 3rd quadrant using that point and the x-axis as sides.
tangent is positive in the 3rd quadrant
tangent is opposite side over adjacent side. Pythagorean theorem not even required for this one.
 
Originally posted by: DrPizza
Anyway, .754 isn't an exact value.
3rd quadrant...
draw a right triangle in the 3rd quadrant using that point and the x-axis as sides.
tangent is positive in the 3rd quadrant
tangent is opposite side over adjacent side. Pythagorean theorem not even required for this one.
Click to expand...

:thumbsup:


I remember when I used to show my trig teacher decimal answers and he used to give me a "WTF is this?!" look.

I would have to walk back to my desk and work the problem out correctly😱
 
Originally posted by: StevenYoo
if -3,-4 is the point on the terminal side, then using arctan, we can see that the angle terminating in Quadrant III is 53 degrees.

so that means the angle with respect to the origin is -143 degrees. (-90 from going backwards through Quad IV and then the additional 53).

so tan(-143) = 0.754

i think i did this wrong, but whatever
Click to expand...

if you read "arctan" as "the angle whose tangent is", then you did this on your calculator:
"The angle whose tangent is 4/3"**** is 53 degrees.
3rd quadrant... -143 degrees...
find the tangent of 143 degrees....

You actually already answered the question at the point where I put in the asterisks.
The rest of it was working in a circle.
 
Originally posted by: DrPizza
Originally posted by: StevenYoo
if -3,-4 is the point on the terminal side, then using arctan, we can see that the angle terminating in Quadrant III is 53 degrees.

so that means the angle with respect to the origin is -143 degrees. (-90 from going backwards through Quad IV and then the additional 53).

so tan(-143) = 0.754

i think i did this wrong, but whatever
Click to expand...

if you read "arctan" as "the angle whose tangent is", then you did this on your calculator:
"The angle whose tangent is 4/3"**** is 53 degrees.
3rd quadrant... -143 degrees...
find the tangent of 143 degrees....

You actually already answered the question at the point where I put in the asterisks.
The rest of it was working in a circle.
Click to expand...

haha self pwned
 
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