Originally posted by: purbeast0
Originally posted by: Born2bwire
No, he only knows his own age. Like I said, one could make the argument that you could discern age from one's appearance. But you could easily choose a number that would have no bearing. Even better, the last four digits of your SSN. So the guy looking at the slips only knows his salary and SSN, and only has either the sum of the salary and SSN or the last four digits of an SSN but he does not know which one is associated with which individual.Originally posted by: purbeast0
Originally posted by: Born2bwire
Originally posted by: purbeast0
Here's one from an interview I had:
You have 3 guys in a room. No one can know the salary of what the other people makes, however when they all leave the room, they must know the average salary of the 3 people in the room. How do they do this?
(and remember, no one can know anyone elses salary).
They write down on different slips of paper the sum of their salary and age and just their age. Then one person adds up the sums of salary and ages and subtracts the individual ages and divides by three.
if they write their age on that slip of paper with the age + salary, then the guy who does the total math will know the individual salaries because he can subract it before he ads them.
You are on the right track but I feel you aren't explaining it clearly. You basically said each person writes the following on a piece of paper.
1. Total of salary + SSN
2. SSN
They then hand that paper to 1 person, and that 1 person adds them all up then subtracats. However since he now has the other 2 people's paper, he can subtract the SSN from the total, resulting in the salary. It doesn't matter if he knows who's is who's, because he still knows the exact salary of the other 2 guys in the room.
They cannot know the exact salaries at all.
Originally posted by: Born2bwire
Originally posted by: purbeast0
Originally posted by: Born2bwire
No, he only knows his own age. Like I said, one could make the argument that you could discern age from one's appearance. But you could easily choose a number that would have no bearing. Even better, the last four digits of your SSN. So the guy looking at the slips only knows his salary and SSN, and only has either the sum of the salary and SSN or the last four digits of an SSN but he does not know which one is associated with which individual.Originally posted by: purbeast0
Originally posted by: Born2bwire
Originally posted by: purbeast0
Here's one from an interview I had:
You have 3 guys in a room. No one can know the salary of what the other people makes, however when they all leave the room, they must know the average salary of the 3 people in the room. How do they do this?
(and remember, no one can know anyone elses salary).
They write down on different slips of paper the sum of their salary and age and just their age. Then one person adds up the sums of salary and ages and subtracts the individual ages and divides by three.
if they write their age on that slip of paper with the age + salary, then the guy who does the total math will know the individual salaries because he can subract it before he ads them.
You are on the right track but I feel you aren't explaining it clearly. You basically said each person writes the following on a piece of paper.
1. Total of salary + SSN
2. SSN
They then hand that paper to 1 person, and that 1 person adds them all up then subtracats. However since he now has the other 2 people's paper, he can subtract the SSN from the total, resulting in the salary. It doesn't matter if he knows who's is who's, because he still knows the exact salary of the other 2 guys in the room.
They cannot know the exact salaries at all.
Well I guess you could make that argument since he could match up the handwriting between the slips. A way to fix that would be one person collects the sums and adds them up while another person collects the SSN and adds them up and they give the numbers to the third person who calculates the average. That way they cannot see which SSN goes with which sum.
Originally posted by: purbeast0
yah that idea would work too.
now you guys need to work on the 2nd one. that one took me a little bit longer to get the answer to at the interview.
Dump gasoline on them, and set it on fire in 45 minutes.Originally posted by: BigJ
I'm not going to give the 2nd one away cause I've had it before for EC, but it's painfully obvious once you hear the solution. It's one of those DOH! moments.
Originally posted by: Thraxen
Fuse Problem:
Light the first fuse on each end. Will take 30 minutes to burn. Light the second fuse on each end after the first one has been burning for 15 minutes. 45 minutes total.
Originally posted by: dullard
Dump gasoline on them, and set it on fire in 45 minutes.Originally posted by: BigJ
I'm not going to give the 2nd one away cause I've had it before for EC, but it's painfully obvious once you hear the solution. It's one of those DOH! moments.
May I get partial credit?Originally posted by: BigJ
I'm sorry, but napalm was the correct answer.
Originally posted by: BigJ
Originally posted by: Thraxen
Fuse Problem:
Light the first fuse on each end. Will take 30 minutes to burn. Light the second fuse on each end after the first one has been burning for 15 minutes. 45 minutes total.
Your solution works because he asked a variation of the original puzzle. In the original, you have no way of telling time, and you're supposed to be able to tell exactly when 45 minutes has passed.
Originally posted by: dullard
May I get partial credit?Originally posted by: BigJ
I'm sorry, but napalm was the correct answer.
Oh, I wanted a shrubbery.Originally posted by: BigJ
Originally posted by: dullard
May I get partial credit?Originally posted by: BigJ
I'm sorry, but napalm was the correct answer.
You can get a collectable Hello Kitty Wall Swatch!
If I sat down for a couple of hours and had my discrete mathematics book out I could solve it.Originally posted by: Atheus
Einstein's riddle. Apparently only 2% of the population can solve it.
1. In a street there are five houses, painted five different colours.
2. In each house lives a person of different nationality
3. These five homeowners each drink a different kind of beverage, smoke different brand of cigar and keep a different pet.
Hints:
1. The Brit lives in a red house.
2. The Swede keeps dogs as pets.
3. The Dane drinks tea.
4. The Green house is next to, and on the left of the White house.
5. The owner of the Green house drinks coffee.
6. The person who smokes Pall Mall rears birds.
7. The owner of the Yellow house smokes Dunhill.
8. The man living in the centre house drinks milk.
9. The Norwegian lives in the first house.
10. The man who smokes Blends lives next to the one who keeps cats.
11. The man who keeps horses lives next to the man who smokes Dunhill.
12. The man who smokes Blue Master drinks beer.
13. The German smokes Prince.
14. The Norwegian lives next to the blue house.
15. The man who smokes Blends has a neighbour who drinks water.
WHO OWNS THE FISH?
Originally posted by: Thraxen
Originally posted by: BigJ
Originally posted by: Thraxen
Fuse Problem:
Light the first fuse on each end. Will take 30 minutes to burn. Light the second fuse on each end after the first one has been burning for 15 minutes. 45 minutes total.
Your solution works because he asked a variation of the original puzzle. In the original, you have no way of telling time, and you're supposed to be able to tell exactly when 45 minutes has passed.
Hmm... so there is another solution that doesn't require the ability to tell time. I'll have to think a bit more on that.
Originally posted by: Garet Jax
Originally posted by: pontifex
Originally posted by: Garet Jax
You have nine balls. 8 are physically identical in weight and dimensions. 1 is the identical dimension as the others, but is a different weight.
You have an equal arm balance and are allowed 3 weighings. How do you determine the 1 ball that is different than the other 8 and whether it is heavier or lighter than the other 8.
pick each one up until you find one thats heavier than the others. don't even need to use the balance.
Difference in weight is indistinguishable by a human and you are only allowed 3 weighings.
Originally posted by: Glavinsolo
You weigh 4 v 4
find which is lighter
You weigh 2 v 2
find which is lighter
You weigh 1 v 1
I am on the 2nd page of this thread btw as I post this
Originally posted by: DaShen
***SOLUTION***
Light 3 ends.
Once the first one burns out, light the 4th end
30 minutes for the first fuse plus the remaining 30 minutes on the second fuse is halved (15 minutes) = 45 minutes
Originally posted by: Garet Jax
Originally posted by: Glavinsolo
You weigh 4 v 4
find which is lighter
You weigh 2 v 2
find which is lighter
You weigh 1 v 1
I am on the 2nd page of this thread btw as I post this
Not quite because you are assuming you're looking for a lighter ball.
Originally posted by: Thraxen
Fuse Problem:
Light the first fuse on each end. Will take 30 minutes to burn. Light the second fuse on each end after the first one has been burning for 15 minutes. 45 minutes total.
Originally posted by: allisolm
Originally posted by: Garet Jax
Originally posted by: Glavinsolo
You weigh 4 v 4
find which is lighter
You weigh 2 v 2
find which is lighter
You weigh 1 v 1
I am on the 2nd page of this thread btw as I post this
Not quite because you are assuming you're looking for a lighter ball.
And not quite because there are 9 balls.
Originally posted by: Glavinsolo
Here is one:
A woman parallel parks a car in between two other cars.
How is this possible?
