Anyone familiar with SOPs and POSs?

konakona

Diamond Member
May 6, 2004
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damn, studying for the test and it turns out there is no one else to ask around. googling doesnt prove that helpful either :eek:

how would you turn a SOP to into a POS when there is only one product term with no ORs?

i.e. ABC (SOP) -> ? (POS)
 

konakona

Diamond Member
May 6, 2004
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well what i am trying to do is to get the product of sums from a single product term that has no missing term. how would i turn this into POS term?
 

ThisIsMatt

Banned
Aug 4, 2000
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This sounds vaguely familiar...

*runs screaming from the thread back to his advanced networking studying*
 

konakona

Diamond Member
May 6, 2004
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ok, i got this solution from somewhere, but dont see how they go about it to get the answer...

AB'C=(A+B+C)(A'+B+C)(A+B'+C)(A'+B'+C)(A+B+C')(A+B'+C')(A'+B'+C')

demorgan's theorem? o_O
 

dighn

Lifer
Aug 12, 2001
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take the complement of AB'C (ABC+A'BC+ABC'...) and complement again using demorgans
 

konakona

Diamond Member
May 6, 2004
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wouldnt that send you right back to your original EQ (AB'C)?
i kinda did it but in a weird way...

the question really was finding a Product of Maxterms from Sum of Minterms, the SoM being AB'C. what i did was :

A'BC = (A'+0)(B+0)(C+0)
(A'+BB'+CC')(B+AA'+CC')(C+AA'+BB')=((A'+B)(A'+B')+CC')((B+A)(B+A')+CC')((C+A)(C+A')+BB')
=((A'+B)(A'+B')+C)((A'+B)(A'+B')+C')((B+A)(B+A')+C)((B+A)(B+A')+C')((C+A)(C+A')+B)((C+A)(C+A')+B')
=(A'+B+C)(A'+B'+C)(A'+B+C')(A'+B'+C')(B+A+C)(B+A'+C)(B+A+C')(B+A'+C')(C+A+B)(C+A'+B)(C+A+B')(C+A'+B')
=(A'+B+C)(A'+B'+C)(A'+B+C')(A'+B'+C')(A+B+C)(A+B+C')(A+B'+C)

is this a valid approach? :eek: