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Any EE/communication experts?

T

tontod

Diamond Member
I've stumbled upon this problem, and not sure how to go about it:

"A new modulation scheme is being planned for a 28.8 Kbps modem in a bandwidth of 4 KHz. If we use a baud rate of 3600 signal changes per second, how many discrete levels of signal modulation will be required to achieve our data rate of 28.8 Kbps"

I think the baud rate is going to be less than the bit rate given, but not sure how to calculate it. I was looking at using the Nyquist formula, but it does not have baud rate in the formula. Anyone have any ideas?
 
I think the answer is 2^8 = 256. Can anyone confirm this? I got 8 as number of bits by dividing the data rate by the baud rate, and taking it to a power of 2 to get discrete number of levels.
 
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