another gr 11 math ?

abracadabra1

Diamond Member
Nov 18, 1999
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i don't have a clue of what the hell you wrote there...but my advice is find the common denominator and then subtract (i think that's a substraction sign you have there).
then, after that, cancel out, if possible.
 

Mday

Lifer
Oct 14, 1999
18,647
1
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speg, i really have no idea what you wrote...

--

btw speg, grade 11 math to me is calculus ;-)
 

Pretender

Banned
Mar 14, 2000
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Oh, i get it, the ~'s are spaces...so the problem is

(5x/3y) - ((8x+2y) / 7x)

It's an easy problem but I can't find a pencil to write it down and work with it, and typing it out would be hell.
 

speg

Diamond Member
Apr 30, 2000
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www.speg.com
ya sorry, it is a minus, just ignore the ~'s. ( it would just all crowd together without them)

you could also write it like this, i guess:

[ 5x/3y ] - [ (8x+2y)/7x ]
 

Pretender

Banned
Mar 14, 2000
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Ah, found a pen.
Basically, make it a common denominator, so you get

(35 - (24x+6y))
---------------
21xy

simplify, and get

11x-6y
------
21xy


you can probably simplify it further, but I'm too lazy
 

Pretender

Banned
Mar 14, 2000
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Yeah, your fraction is right. The only way to factor the top is with the quadratic formula, and you get

24y -+ (1416y^2)^(1/2)
---------------------
70

which becomes

12y -+ y * (354)^(1/2)
---------------------
35



BTW, something to the 1/2 power is the same as the square root, since there's no sqr. root symbol here...
 

xtreme2k

Diamond Member
Jun 3, 2000
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I think the answer speg got is simplified enough.

But then basically, it is 'expended' not 'simplfied'
 

jyrixx

Senior member
May 31, 2000
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ok, i'm getting (5x/3y) - x

which is probably really wrong.. i'm rusty on the ole algebra...