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An extremely simple physics question...

By applying a pressure of 200 atm (which is about 200x10^5 N/m^2) you can compress water to 99% of its usual volume. Estimate the work required to compress a liter (0.001 m^3) of water by this amount.

The textbook gives an answer of 100 N*m.

But in this problem, W = -P*?V = -(200x10^5)*(0.0009-.001) = 200 N*m




 
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