Algebra Question

[MegaloManiaK]

I have the following equations

A X B = CB
B + C = A

Can anyone tell me what method would be used to solve here?

 

[minendo]

Divide both sides of the top one by B.

 

[crt1530]

Is CB a two digit number?

 

[MegaloManiaK]

Originally posted by: minendo
Divide both sides of the top one by B.

I can do that but it gives me A=C and B=0 but that doesn't help me find A and C. I think theres something more to it that will produce a curve with multiple solutions. I could be totaly wrong and its a simple trick.

 

[MegaloManiaK]

Originally posted by: crt1530
Is CB a two digit number?

I dont think so, but i will explore this possibility (a friend asked me if i could solve it algebraicly)

 

[minendo]

Originally posted by: MegaloManiaK

Originally posted by: minendo
Divide both sides of the top one by B.

I can do that but it gives me A=C and B=0 but that doesn't help me find A and C. I think theres something more to it that will produce a curve with multiple solutions. I could be totaly wrong and its a simple trick.

A and C could be any number.

 

[Stojakapimp]

can we assume that AxB = AB?

 

[MegaloManiaK]

Originally posted by: Stojakapimp
can we assume that AxB = AB?

Unfortunatly no, the A X B is exactly how it appears in the original problem as well as AB

I asked the person who sent it to me and claims to have solved it to clarify if AB is a 2 digit number.

 

[gsiener]

A X B = CB
B + C = A

Just set it up so that
A x B = 10C + B
and
B+C = A

also, CB is two digits which means 9< A x B < 100
substitute to get:

(B+C)xB=10C + B

You should be able to get the rest from there.

 

[shenaniganz]

Originally posted by: MegaloManiaK
I have the following equations

A X B = CB
B + C = A

Can anyone tell me what method would be used to solve here?

So what you are asking is A*X*C = C*B and B+C=A (obviously)? What variable are you solving for?

 

[gsiener]

oh is that an X or multiply?

 

[MegaloManiaK]

Originally posted by: gsiener
oh is that an X or multiply?

Its multiply. I think you got it in your above post.

 

[notfred]

Originally posted by: MegaloManiaK

Originally posted by: gsiener
oh is that an X or multiply?

Its multiply. I think you got it in your above post.

In that case, A X B = AB

AB = CB

A = C

B + A = A

B = 0

A = C = Any real number

 

[gsiener]

but that's not quite true
a and c have bounds based on the fact that cb is a two digit number

 

[minendo]

Originally posted by: gsiener
but that's not quite true
a and c have bounds based on the fact that cb is a two digit number

CB represents CxB. When B=0, CB is a single digit number.

 

[notfred]

Originally posted by: minendo

Originally posted by: gsiener
but that's not quite true
a and c have bounds based on the fact that cb is a two digit number

CB represents CxB. When B=0, CB is a single digit number.

Well, it could be 00.