the first question is this:
1.) The set of all real numbers that, when tripled and then halved, are more than 5 units distance from 2:
a.) {x|xeR,14/3<x or x,-2} b.) (neg. infinite, -2) c.) (14/3, infinite) d.) (neg. infinite, 14/3) U (-2,infinite) E.) (-2, infinite)
my work - ok so i broke it down as this:
|(3x/2)-2| > 5
[3x/2-2>5 and 3x/2 - 2 < -5]
[3x-4>10 and 3x-4<-10]
[3x>14] and [3x<-6]
x>14/3 and x<-2
so the answer must be a.) {x|xeR,14/3<x or x,-2}
right?
ok one more plz hold tight -
6.) The solution set for 2x+1<1-x/2<8 is: a) (neg. infinite, -15) b.) (-15, infinite) c.) (-15, -1/5) d.) (3/5,15)
e.) (neg infinite, -1/5)
my work: 2x+1 < 1-x/2 < 8
[2x+1 < 1-x/2 or 1-x/2 < 8]
[4x+2<1-x or 1-x < 16]
[4x<-1 or -x<15]
[5x<-1 or x> -15]
[x< -1/5 or x> -15]
which leaves me with (-15, -1/5) which is "C" if my math is right.
1.) The set of all real numbers that, when tripled and then halved, are more than 5 units distance from 2:
a.) {x|xeR,14/3<x or x,-2} b.) (neg. infinite, -2) c.) (14/3, infinite) d.) (neg. infinite, 14/3) U (-2,infinite) E.) (-2, infinite)
my work - ok so i broke it down as this:
|(3x/2)-2| > 5
[3x/2-2>5 and 3x/2 - 2 < -5]
[3x-4>10 and 3x-4<-10]
[3x>14] and [3x<-6]
x>14/3 and x<-2
so the answer must be a.) {x|xeR,14/3<x or x,-2}
right?
ok one more plz hold tight -
6.) The solution set for 2x+1<1-x/2<8 is: a) (neg. infinite, -15) b.) (-15, infinite) c.) (-15, -1/5) d.) (3/5,15)
e.) (neg infinite, -1/5)
my work: 2x+1 < 1-x/2 < 8
[2x+1 < 1-x/2 or 1-x/2 < 8]
[4x+2<1-x or 1-x < 16]
[4x<-1 or -x<15]
[5x<-1 or x> -15]
[x< -1/5 or x> -15]
which leaves me with (-15, -1/5) which is "C" if my math is right.
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