Algebra 2 Homework II

Rip the Jacker

Diamond Member
Dec 29, 2004
5,415
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Directions: Find the roots of each polynomial equation

9. x^3 -5x^2 +2x +8 . I graphed this and got: -1, 2, 4
10. x^3 +x^2 -17x +15 . I graphed this and got -5, 1, 3
11. 2x^3 + 13x^2 +17x -12. I graphed this and I got -4, -3, and what looks to be .3, but I'm not 100% sure and I tried looking at 2nd, table (ti-83)

Am I doing this right?
 

spunkz

Golden Member
Jul 16, 2003
1,467
0
76
Originally posted by: Rip the Jacker
Directions: Find the roots of each polynomial equation

9. x^3 -5x^2 +2x +8 . I graphed this and got: -1, 2, 4
10. x^3 +x^2 -17x +15 . I graphed this and got -5, 1, 3
11. 2x^3 + 13x^2 +17x -12. I graphed this and I got -4, -3, and what looks to be .3, but I'm not 100% sure and I tried looking at 2nd, table (ti-83)

Am I doing this right?

plug the numbers back in the equation for x. if you get 0, you're good
 

Goosemaster

Lifer
Apr 10, 2001
48,775
3
81
Originally posted by: wobbuffet
Originally posted by: Goosemaster
synthetic division. I thought I told you that last time:|

LMAO :gift::laugh:

damn lazy punks don't realize that progressive learning means that you don't forget what people teach you as your classes REQUIRE you to retain that info for future use,
 

Goosemaster

Lifer
Apr 10, 2001
48,775
3
81
And RIP the Jacker..I don't mean to be mean....it's just that we already told you how to do this...

Why not try harder and save bandwidth so neffers like me can neff that much more?:)


*promply removes his foot from its present postion lodged up RIP the Jackers ass*

 

Rip the Jacker

Diamond Member
Dec 29, 2004
5,415
1
76
Originally posted by: Goosemaster
And RIP the Jacker..I don't mean to be mean....it's just that we already told you how to do this...

Why not try harder and save bandwidth so neffers like me can neff that much more?:)


*promply removes his foot from its present postion lodged up RIP the Jackers ass*

The directions were different this time, and my teacher told me to use a graphing calculator instead of manually solving... Didn't know you can just use the same method as last time.

Last time, it gave you x-1, x-2, and told you to use synthetic division. These directions ARE different.
 

Elderly Newt

Senior member
May 23, 2005
430
0
0
Originally posted by: Rip the Jacker
Originally posted by: InlineFour
use your "zeros" button.

Wtf do I do for Left and Right Bound? I get an error...

Assuming you're using a Texas Instruments Graphing Calculator:

I assume you're getting a "NO SIGN CHANGE ERROR"? This is caused by having your left and right bound either both above the x axis or both below the x axis when finding a zero (x-intercept). The left and right bound tells the calculator the interval in which to look for a zero. Logically, if the inverval is completely below or completely above the X-axis, it will not contain a zero.

When it asks for LEFT bound, simply pick a point on the graph that is to the LEFT of the zero. Select the point and hit enter. When it asks for RIGHT bound, pick a point on the graph that is to the RIGHT of the zero. Select the point and hit enter. It will now say "guess?" Hit enter. It will now calculate and display the value of the zero. Do this as many times as you need until you've gotten all the zeros.
 

Goosemaster

Lifer
Apr 10, 2001
48,775
3
81
Originally posted by: Rip the Jacker
Originally posted by: Goosemaster
And RIP the Jacker..I don't mean to be mean....it's just that we already told you how to do this...

Why not try harder and save bandwidth so neffers like me can neff that much more?:)


*promply removes his foot from its present postion lodged up RIP the Jackers ass*

The directions were different this time, and my teacher told me to use a graphing calculator instead of manually solving... Didn't know you can just use the same method as last time.

Last time, it gave you x-1, x-2, and told you to use synthetic division. These directions ARE different.

1) you should have posted the details so we wouldn't chew you out

2) perhaps the directiosn ARE different, but you DID NOT POST THEM, you you DESERVE what you got:p
 

Rip the Jacker

Diamond Member
Dec 29, 2004
5,415
1
76
Originally posted by: Goosemaster
Originally posted by: Rip the Jacker
Originally posted by: Goosemaster
And RIP the Jacker..I don't mean to be mean....it's just that we already told you how to do this...

Why not try harder and save bandwidth so neffers like me can neff that much more?:)


*promply removes his foot from its present postion lodged up RIP the Jackers ass*

The directions were different this time, and my teacher told me to use a graphing calculator instead of manually solving... Didn't know you can just use the same method as last time.

Last time, it gave you x-1, x-2, and told you to use synthetic division. These directions ARE different.

1) you should have posted the details so we wouldn't chew you out

2) perhaps the directiosn ARE different, but you DID NOT POST THEM, you you DESERVE what you got:p

Um. They are the first thing in bold?


Directions: Find the roots of each polynomial equation
 

Elderly Newt

Senior member
May 23, 2005
430
0
0
Originally posted by: Rip the Jacker
Originally posted by: Goosemaster
Originally posted by: Rip the Jacker
Originally posted by: Goosemaster
And RIP the Jacker..I don't mean to be mean....it's just that we already told you how to do this...

Why not try harder and save bandwidth so neffers like me can neff that much more?:)


*promply removes his foot from its present postion lodged up RIP the Jackers ass*

The directions were different this time, and my teacher told me to use a graphing calculator instead of manually solving... Didn't know you can just use the same method as last time.

Last time, it gave you x-1, x-2, and told you to use synthetic division. These directions ARE different.

1) you should have posted the details so we wouldn't chew you out

2) perhaps the directiosn ARE different, but you DID NOT POST THEM, you you DESERVE what you got:p

Um. They are the first thing in bold?


Directions: Find the roots of each polynomial equation

He's talking about the fact that you now have to use a graphing calculator instead of manually solving.
 

TuxDave

Lifer
Oct 8, 2002
10,571
3
71
What's the point of doing homework if all it's testing you on is how to use your calculator?
 

Fenixgoon

Lifer
Jun 30, 2003
33,332
12,915
136
Originally posted by: Goosemaster
Originally posted by: wobbuffet
Originally posted by: Goosemaster
synthetic division. I thought I told you that last time:|

LMAO :gift::laugh:

damn lazy punks don't realize that progressive learning means that you don't forget what people teach you as your classes REQUIRE you to retain that info for future use,

meh, i forgot synthetic division, and i havent used it since.. currently doing taylor/mclauren series polynomials in calc2/intro to diff eq :D
 

Goosemaster

Lifer
Apr 10, 2001
48,775
3
81
Originally posted by: Elderly Newt
Originally posted by: Rip the Jacker
Originally posted by: Goosemaster
Originally posted by: Rip the Jacker
Originally posted by: Goosemaster
And RIP the Jacker..I don't mean to be mean....it's just that we already told you how to do this...

Why not try harder and save bandwidth so neffers like me can neff that much more?:)


*promply removes his foot from its present postion lodged up RIP the Jackers ass*

The directions were different this time, and my teacher told me to use a graphing calculator instead of manually solving... Didn't know you can just use the same method as last time.

Last time, it gave you x-1, x-2, and told you to use synthetic division. These directions ARE different.

1) you should have posted the details so we wouldn't chew you out

2) perhaps the directiosn ARE different, but you DID NOT POST THEM, you you DESERVE what you got:p

Um. They are the first thing in bold?


Directions: Find the roots of each polynomial equation

He's talking about the fact that you now have to use a graphing calculator instead of manually solving.

exactly.
 

Elderly Newt

Senior member
May 23, 2005
430
0
0
Originally posted by: TuxDave
What's the point of doing homework if all it's testing you on is how to use your calculator?

A graphing calculator is a very powerful tool, and knowing how to use it properly and efficiently is essential. Although, you're right: it's pretty pointless if you don't understand the concept you're using it for.
 

JustAnAverageGuy

Diamond Member
Aug 1, 2003
9,057
0
76
2x^3 + 13x^2 +17x -12. looks closer to .5 to me ;)

-4......2.....13.....17.....-12
..................-8.....-20.....12
-3......2.......5......-3.........0
..................-6......3
.........2......-1.......0

2x-1 = 0

Solve for x