c'mon the math isn't that hard
16x9 is the ratio of the sides, right?
so the diagonal (c) is given by:
a^2 + b^2 = c^2
c^2 = 16^2 + 9^2 = 337
c = 18.36
so take any widescreen measurement like 30", divide it by 18.36 and that will give you the critical component. (30/18.36=1.63)
you just take that 1.63 and multiply it by 16 for the width or 9 for the height.
w: 1.63 x 16 = 26.08
h: 1.63 x 9 = 14.67
for a 27" 4:3 tv, we have a c of 5, so a component of 27/5 = 5.4.
w: 5.4 x 4 = 21.6
h: 5.4 x 3 = 16.2
so your tube is going to be about 4.5 inches wider and 1.5 inches shorter. of course, you have to take into account the borders and such, but there's your basic answer.
Originally posted by: SuperShaz
Its 30 inches across, but how tall is it? I'm just wondering about watching normal TV. Would it be smaller than my 4:3 27" TV or bigger?
- SuperShaz