AHHH, What the heck! *pic*

jinduy

Diamond Member
Jan 24, 2002
4,781
1
81
so the root of the problem was the 2nd line of the proof?

a^2 - b^2 = ab - b^2

0 = 0
 

MAME

Banned
Sep 19, 2003
9,281
1
0
there's another issue

b(a-b)

that would be b * 0, but they have it as just b left over
 

Jzero

Lifer
Oct 10, 1999
18,834
1
0
4th line to 5th line.
If A = B, then A - B = 0 so dividing both sides by (A - B) is division by 0.
 

RaynorWolfcastle

Diamond Member
Feb 8, 2001
8,968
16
81
NO you're all wrong 2 is equal to one, but if 2 = 1, then 4 = 2 = 1 and 8 = 4 = 2 = 1 and so on. In fact all integer numbers are equal to each other, you've destroyed math! :|
 

MAME

Banned
Sep 19, 2003
9,281
1
0
Originally posted by: RaynorWolfcastle
NO you're all wrong 2 is equal to one, but if 2 = 1, then 4 = 2 = 1 and 8 = 4 = 2 = 1 and so on. In fact all integer numbers are equal to each other, you've destroyed math! :|

:Q
 

Yzzim

Lifer
Feb 13, 2000
11,990
1
76
Originally posted by: RaynorWolfcastle
NO you're all wrong 2 is equal to one, but if 2 = 1, then 4 = 2 = 1 and 8 = 4 = 2 = 1 and so on. In fact all integer numbers are equal to each other, you've destroyed math! :|

hope my computer doesn't figure that out :Q
 

illusion88

Lifer
Oct 2, 2001
13,164
3
81
Originally posted by: Yzzim
Originally posted by: RaynorWolfcastle
NO you're all wrong 2 is equal to one, but if 2 = 1, then 4 = 2 = 1 and 8 = 4 = 2 = 1 and so on. In fact all integer numbers are equal to each other, you've destroyed math! :|

hope my computer doesn't figure that out :Q

quick, close the page! It may be looking! :shocked;