A xW resistor has XC/min of charge flowing through it. How much power is dissipated?

[MikeMike]

is the formula for this just P = I^2 * R??

 

[iwantanewcomputer]

unless it's some weird kind of resistor that doesn't obey the normal laws...yes

Twinkle twinkle little star,
power equals I squared R

 

[cavemanmoron]

did you bring your school book home?

Read the book??????????

 

[MikeMike]

Originally posted by: cavemanmoron
did you bring your school book home?

Read the book??????????

dont have it, and you couldnt jsut answer yes/no? MORAN.

 

[Engineer]

Originally posted by: nourdmrolNMT1
MORAN.

It's "MORON"

 

[MikeMike]

so am i correct in assuming that if the resistor has 190C/min flowing through it and a resistance of 2kOhms, then i would do:

190^2 *2000 and get 72200000 watts?

 

[cavemanmoron]

Originally posted by: nourdmrolNMT1
so am i correct in assuming that if the resistor has 190C/min flowing through it and a resistance of 2kOhms, then i would do:

190^2 *2000 and get 72200000 watts?

O hms law,

Man I get a headache looking at that.

It has been 29 years,since I was in High School.

http://members.tripod.com/~masterslic/olcalculator.html

 

[walla]

current should be in Coulombs per second (otherwise known as the Ampere)

So divide your C/min by 60 before you square it.

 

[cavemanmoron]

http://www.aralb.org/Commitees/Technical/Ohms_law/ohmslaw.htm

http://www.mindhertz.com/OhmsLaw.php

http://www.free-electronic-circuits.com/calculators/ohms.html

http://www.riedon.com/riedon_calculator.htm

 

[xirtam]

Coulomb is Charge, which is Q. You have to convert your charge per time unit to amperes before you can plug it into ohm's law.