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9600 Pro Memory Bandwidth question

b4u

Golden Member
Hi,

Looking at ATI specifications, I see:

Frame Buffer: 128Mb DDR
Memory Interface: 128-bit
Rendering Pipelines: 4
Pixel Fillrate (Gpixels/sec): 1.6
Engine Clock (MHz): 400
Memory Clock (MHz): 600
Output Connectors: VGA + TV + DVI

My questions:

The bandwidth of the GPU should be: 400*128/8=6400GB
The bandwidth of the DDR should be: 600*128/8=9600GB

[1] Are my calculations correct? Do I have some sparing Bandwidth on the DDR side? That would bring me some room to OC the core without touching the DDR settings.

[2] When someone say 400/300, the settings are related to GPU/DDR frequencies, right? (just a confirmation)


Thanks
 
1] Your bandwidth calculations are correct.

2] Correct.

The 9600pro is 400/300 (DDR) and comes with 2.86ns or 3.3ns Samsung DDR. The cards with the 2.8 stuff usually cost about $20 more than the cards like the Sapphire OEM/bulk with 3.3 memory.

Here in Canada ...

retail 9600pro ... ... ... .... $255 ... (2.8ns)
OEM Sapphire 9600pro ... $ 225 ... (3.3ns)

1000/2.86ns = 350mhz which is the maximum rated speed for that memory. Usually overclocks to about 350-365.

1000/3.3ns = 300mhz which is the maximum rated speed for that memory. Usually overclocks to about 310-315


When overclocking, if you overclock both the memory and GPU 10% you can improve performance 10%. If you just turn up the GPU 10% faster you might only get (1/2) = 5% better performance. Same for only turning up just the memory speeds.
 
Originally posted by: Blastman
1000/2.86ns = 350mhz which is the maximum rated speed for that memory. Usually overclocks to about 350-365.

1000/3.3ns = 300mhz which is the maximum rated speed for that memory. Usually overclocks to about 310-315

Thanks for the reply 🙂

One more thing ... why the use of 1000 in the above calculations? What does it stands for?

Thanks
 
One more thing ... why the use of 1000 in the above calculations? What does it stands for?
I used 1000 to change the 2.86 billionth/sec into 350 million-cycles-per-second (350MHz).

?.

ns = nanoseconds = billionth/sec.

2.86ns = 0.00000000286 seconds ? = 2.86 x 10E-9

1/2.86ns = 0.350 x 10E 9 ? or ? 0.350 GHz? (Giga = billion)

finally

1000/ 0.350 GHz = 350 MHz

...

ADD: If something cycles in 2.86ns, how many times per second does it cycle?

1sec/0.00000000286 = 350,000,000 = 350MHz ? (Mega = 1,000,000)



 
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