6800 vanilla only has 5 vertex units (vs. 6)?

reallyscrued

Platinum Member
Jul 28, 2004
2,618
5
81
it means in the same situation as a GT, it will have 5/6 of the performance.

(yeah i dunno....)
 

rbV5

Lifer
Dec 10, 2000
12,632
0
0
I remember B3D suggesting that (and a long thread IIRC) when the 6800standard was released some time ago.

Reference GeForce 6800 graphics card provided by NVIDIA Corp. and used by X-bit labs? laboratory in Tallinn, Estonia, scored identical fps in Xbitmark vertex shader test against NVIDIA?s reference GeForce 6800 Ultra graphics card working at the same clock-speeds, indicating equal per MHz geometry performance of the 6800 model against the ?Ultra? model.

Is he trying to say that the reference NV cards were using the full 6 VS, and that partner cards could be as low as 4? I would like to warn everybody going to buy non-Ultra 6800. We have already detected $350 OEM Leadtek [GeForce] 6800 graphics cards in Russia, which have 2 disabled quads and 2 disabled vertex processors,? Mr. Nikolaychuk added.

are these 6800le cards? (8pipes and 4 VS) or is he saying Leadtek is passing them off as 6800 standard cards?

hehe, I'd like to check mine now:)
 

orangat

Golden Member
Jun 7, 2004
1,579
0
0
It shouldn't matter that much for a 6800 to be missing 1 vertex proc since its got less pixel pipes anyway.

Whats disturbing is that the initial sample sent by Nvidia to x-bitlabs for testing seems to have all vertex procs available.