"The plane that passes through the line of intersection of the planes x - z = 1 and y + 2z = 3 and is perpendicular to the plane x + y - 2z = 1"
I've found the line of intersection, by setting z = 0, and finding the cross product of the two normal vectors of the planes given, which in parametric form is:
x = 1 + t, y = 3 - 2t, z = t
From there I can find a point or two as needed..But what's weird about this problem is that the third given plane is perpendicular to the one you're supposed to find..so I'm not quite sure what to do next..
I've found the line of intersection, by setting z = 0, and finding the cross product of the two normal vectors of the planes given, which in parametric form is:
x = 1 + t, y = 3 - 2t, z = t
From there I can find a point or two as needed..But what's weird about this problem is that the third given plane is perpendicular to the one you're supposed to find..so I'm not quite sure what to do next..
