Recent content by lowwall

  1. L

    Clever Programmers: I need to improve the efficiency of this program by 8 orders of magnitude :(

    Not sure how much this will help, but looking at wbwither's list, I notice the following pattern: for any triangular square > 1, the square root of the next triangular square is 6*the square root of the current triangular square - the square root of the previous triangular square i.e. 6*6 -...