** ANOTHER NEW QUESTION! ** Check my last post

** NEW QUESTION! **
A peculiar six-sided die has uneven faces. In particular, the faces showing 1 or 6 are 1 x 1.5 inches, the faces showing 2 or 5 are 1 x 0.4 inches, and the faces showing 3 or 4 are 0.4 x 1.5 inches. Assume that the probability of a particular

face coming up is proportional to its area. We independently roll the die twice. What is the probability that we get doubles?

So calculating the probabilities for each set of numbers you have...

P(1, 6)=.6

P(2, 5)=.16

P(3, 4)=.24

**EDIT:** Would you do 2(.3)(.3)+2(.08)(.08)+2(.12)(.12) = .2216?

Does this mean that the Probility of getting just a 1 is .6?? or is it .3? If you take it as .6, then the sum of the probabilities is 2.0. Im confused about that and everything after that point

if someone can help me out I would really appreciate it!!

THANKS!

**Q:**An internet access provider (IAP) owns two servers. Each server has a

50% chance of being ?down? independently of the other. Fortunately, only one server

is necessary to allow the IAP to provide service to its customers, i.e., only one server

is needed to keep the IAP?s system up. Suppose a customer tries to access the internet

on four different occasions, which are sufficiently spaced apart in time, so that we

may assume that the states of the system corresponding to these four occasions are

independent. What is the probability that the customer will only be able to access the

internet on 3 out of the 4 occasions?

Is the answer (3x3x3x1)/(4x4x4x4) = .105 or (3x3x3x1)x4/(4x4x4x4) = .4218 or neither

any help and explanation would be appreciated

thanks!