A crankshaft, with a diameter of 3.00 cm, rotating at 2200 rpm comes to a halt in 1.50 s.

Q1: What is the tangential acceleration of a point on the surface of the crankshaft?

I think I have to convert 2200 rpm to m/s (velocity), to find the acceleration (change in velocity/1.50s). Then divide the acceleration by the radius. However, I don't know how to do the rpm to m/s conversion.

Q2: How many revolutions does the crankshaft make as it stops?